Carb synch question
Posted: Sun Nov 25, 2012 3:38 am
Ok, so I'm trying to synchronize my carbs, for the second time. (The first time it couldn't get the #1/#3 to even out and then realized that some previous mofo must have lost the standard M4x0.5 screw and put in a standard M4x0.7 which had stripped the threads...
) After taking them off and tapping an M5 screw in there I'm back at it again.
Anyway, here's the question: Does the vacuum go up or down if you open the throttle? It goes down, right? (Bigger opening to the atmosphere, more air gets in, less vacuum.) So the proper direction is to close the throttle on the cylinders that have too low vacuum.
This seems counterproductive because if you *open* the throttle, then the vacuums go up. But that's because the engine is speeding up. Since all cylinders are going at the same speed, higher vacuum means too closed throttle.
The reason I'm asking is because I'm having a hell of a time getting to an even point. When I turn the screw that adjusts front vs back, the two back ones also change relative to each other. Turning the screw that adjusts #1 vs #3 doesn't obviously do anything. I don't know if something's loose or whatever, but it's really frustrating.

Anyway, here's the question: Does the vacuum go up or down if you open the throttle? It goes down, right? (Bigger opening to the atmosphere, more air gets in, less vacuum.) So the proper direction is to close the throttle on the cylinders that have too low vacuum.
This seems counterproductive because if you *open* the throttle, then the vacuums go up. But that's because the engine is speeding up. Since all cylinders are going at the same speed, higher vacuum means too closed throttle.
The reason I'm asking is because I'm having a hell of a time getting to an even point. When I turn the screw that adjusts front vs back, the two back ones also change relative to each other. Turning the screw that adjusts #1 vs #3 doesn't obviously do anything. I don't know if something's loose or whatever, but it's really frustrating.